Feb 19, 2025
w/w→means Both drug as well as preparation has same unit
1% framycetin→1g →100g of the preparation
100g contains 1g framycetin
20 g contains - 1100×20=0.2g
= 0.2 × 1000
= 200mg
Normal saline = 0.9% Nacl solution
- 0.9 Nacl100 ml of solution
We have 15g→ 100 ml
In 0.9g - 10015×0.9=6ml
6ml + 94 ml distilled water
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The Dose is 40 × 10 = 400mg/d = 200mg BD.
250 mg 5ml
1mg →5250
200 mg - 5250200=4ml
1:10,000 means →1gramof adrenaline is present in 10,000 ml of
Solution
1g → 10,000ml
1000mg →10000ml
1mg - 100001000=10ml
Total dose to be given is - 3 × 40kg = 120 mg
40 mg present in 1ml
120 mg -140×120=3ml
Total amount we need to give is = 20,000 × 5 kg = 1,00000 units
We have 5 lac unit per ml
= 1 lac unitPresent → in 1 5=0.2ml
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We need to give 0.1 × 60 kg = 6 units /hr or 6/60 = 0.1u/min
1ml = 0.1 u
500ml = 500 x 0.1 = 50 units
40 u - 1m
50 u - 1 - 40 ×50=1.2ml
Weight is 60 kg?
Iml = 0.2 mg
We have 500 ml in fusion, so total will be
500 × 0.2 = 100mg of lignocaine
- 2g is present in 100ml or
2000 mg present in 100 ml
- 100 mg -1002000×100=5ml
We will take 5ml from the vial and mix it with 500 ml of normal saline
25 mg present in 500 ml
1mg present in = 50025
10 mg (10 x 10-3) =50025 ×10 × 10-3
= 0.2 ml
1 ml contains 60 drops
0.2 ml contains 60 x 0.2 = 12 drops/min
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- 5 IU present in 500 ml
- 5 m/unit 5×10-3u-5005×5×10-3
= 0.5 ml/min
- 1 ml contain 16 drops
So 0.5 contain 8 drops
- 500 mg present in 5 ml.
- 1 ml will be present in 5005ml
- 180 ml will be present in 5005×180
= 1.8 ml
The syringe has 10 divisions per ml.
1ml contain - 10 divisions
1.8 ml contain - 10 x 1.8 = 18 divisions
- every one hour – 200 mg cleared from the body
In 3 hour – 200 x 3 = 600 mg cleared
- The remaining will be 1000 – 600 = 400 mg
- here the drug follows first order kinetics .
every 112hr =75200 eliminated
= 125200=58 will remain
After 112hours, the remaining will be – 200 x 5/8
In 3 hours - 200 x 5858
In 412 hours - 200 x 5858
In 6 hrs - 200 x 585858 = 30.5 mg
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t12=0.7 ×vdCL
= 0.7 ×602.1 L/min=20 min
CLH = H ER x Blood flow
= 0.6 x 1500 ml/min
= 900 ml/min
Loading dose = Vd x target PC
Vd = 0.6 x 50 = 30 L
LD = 30 x 20 mg/L
= 600 mg
Maintenance dose (MD)= CL x target PC
= 10 L/hr x 5 mg/L
= 50 mg / hr
In 6 hr = 50 x 6 = 300 mg.
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MD = CL X target PC
PC =MDCL=60 mh/h50 x 60 ml/h
= 150 mg/ml
= 0.02 mg/ml
= 20 mg/ml
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